Pointer kullanmadan yazılan fonksiyon
#include <stdio.h>
int cubeByValue( int n );
int main()
{
int number = 5;
printf( “The original value of number is %d”, number );
/* pass number by value to cubeByValue */
number = cubeByValue( number );
printf( “nThe new value of number is %dn”, number );
return 0;
}
int cubeByValue( int n ) {
return n * n * n;
}
Pointer kullanılarak yukardaki fonksiyonun tekrar yazılması
#include <stdio.h>
void cubeByReference( int *nPtr );
int main()
{
int number = 5;
printf( “The original value of number is %d”, number );
cubeByReference( &number );
printf( “nThe new value of number is %dn”, number );
return 0;
}
void cubeByReference( int *nPtr )
{
*nPtr = *nPtr * *nPtr * *nPtr; /* cube *nPtr */
}
The original value of number is 5
The new value of number is 125
Fonksiyon İşağretcisi
#include <stdio.h>
int sum(int x, int y)
{
return x + y;
}
int product(int x, int y)
{
return x * y;
}
int difference(int x, int y)
{
return x – y;
}
int main(void)
{
int a = 10;
int b = 5;
int result = 0;
int (*pfun)(int, int); /* Function pointer declaration */
pfun = sum;
result = pfun(a, b); /* Call sum() through pointer */
printf(“npfun = sum result = %d”, result);
pfun = product;
result = pfun(a, b); /* Call product() through pointer */
printf(“npfun = product result = %d”, result);
pfun = difference;
result = pfun(a, b); /* Call difference() through pointer */
printf(“npfun = difference result = %dn”, result);
return 0;
}
pfun = sum result = 15
pfun = product result = 50
pfun =